SQL MOD
The function-call form of the % operator — MOD(a, b) does exactly the same job as a % b.
What & Why
MOD(a, b) is functionally identical to a % b — both return the remainder after division. This is the same pattern seen throughout this track: an operator and an equivalent function existing side by side, differing only in syntax.
See How It Works
BUSINESS QUESTION
Growth wants users assigned to one of four deterministic review buckets.
| id | created_at | country | channel | plan | activated_at | churned_at |
|---|---|---|---|---|---|---|
| 101 | 2024-01-15 09:10:00+00 | US | organic | pro | 2024-01-16 14:25:00+00 | NULL |
| 102 | 2024-02-10 11:05:00+00 | CA | paid | free | NULL | 2024-03-20 10:00:00+00 |
| 103 | 2024-03-12 16:35:00+00 | GB | referral | pro | 2024-03-13 08:15:00+00 | NULL |
| 104 | 2024-04-01 13:20:00+00 | US | organic | free | 2024-04-03 12:00:00+00 | NULL |
EXAMPLE QUERY
SELECT
id AS user_id,
MOD(id, 4) AS review_bucket
FROM growth.users
ORDER BY user_id;RESULT — exact output from the displayed Queryflo rows
| user_id | review_bucket |
|---|---|
| 101 | 1 |
| 102 | 2 |
| 103 | 3 |
| 104 | 0 |
MOD assigns the displayed users to deterministic review buckets.
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